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916 Checkerboard V1 Codehs Fixed -

916 Checkerboard V1 Codehs Fixed -

# 1. Initialize the board with all 0s board = [] for i in range(8): board.append([0] * 8) # 2. Use nested loops to replace 0s with 1s # Goal: Top 3 and bottom 3 rows should have 1s in a checkerboard pattern for row in range(8): for col in range(8): # Check if it's in the top 3 (0-2) or bottom 3 (5-7) rows if row < 3 or row > 4: # Use modulus to create the alternating checkerboard pattern if (row + col) % 2 == 0: board[row][col] = 1 # 3. Print the final board for row in board: print(row) Use code with caution. Copied to clipboard Why this works:

Using this mathematical rule ensures that when you move down to the next row, the pattern automatically offsets itself without requiring complex tracking variables. The Fixed Code Implementation

(frontIsClear()) move(); putBall();

To build a flawless checkerboard pattern, you must calculate the value of a cell based on its unique mathematical coordinates: the and the column index .

Define a function that iterates through each row of your 2D list. Use a list comprehension to convert the integers to strings so they can be joined by spaces for the final display. 4. Avoid Common Errors 916 checkerboard v1 codehs fixed

Keep grinding on those Tracy the Turtle challenges! 🐢💻

: Ensure you are not hardcoding pixel values like 400 or 300 into your loops. Always rely on your calculated variables or the getWidth() and getHeight() functions if specified. Print the final board for row in board:

The instructions require modifications only to the top 3 rows (indices ) and the bottom 3 rows (indices ). The middle two rows (indices ) must remain all

To fix the assignment, you must ensure you are not just printing the final output, but actually modifying the elements of a 2D list (grid) using assignment statements . The autograder specifically checks for code that sets elements to 1 . Fixed Python Code Define a function that iterates through each row

(i + j) % 2 == 0 divides the sum of the indices by 2. If there is no remainder, the position is even, assigning a 0 . Otherwise, it assigns a 1 .

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